Quadratics and Polynomials

TSI Math Study Guide

Quadratics and Polynomials

Polynomial — an expression made of terms with variables raised to whole-number exponents.
Quadratic — a polynomial whose highest exponent is 2, such as 3x2 − 5x + 2.

On the TSI you may need to simplify polynomial expressions, factor polynomials, solve quadratic equations, and evaluate quadratic functions.

Combining like terms

Like terms — the same variables raised to the same powers. x2 and x are not like terms and can’t be combined.
4x2 + 3x − 2x2 + 5x 4x2 − 2x2 = 2x2the x2 terms 3x + 5x = 8xthe x terms 2x2 + 8x

Multiplying polynomials

Monomial × polynomial

Distribute to each term.

3x(x2 − 4x + 5)3x3 − 12x2 + 15x

Binomial × binomial

Distribute each term of the first.

(x + 3)(x + 5)x(x + 5) + 3(x + 5)x2 + 5x + 3x + 15x2 + 8x + 15combine like terms

Some students remember this as FOIL. The distributive property works in every case and is more general.

Factoring polynomials

Factoring — reverses multiplication. x2 + 8x + 15 = (x + 3)(x + 5) because 3 + 5 = 8 and 3(5) = 15. It’s one of the main ways to solve quadratic equations.

Greatest common factor first

Before anything else, check whether every term shares a factor.

6x2 + 18x = 6x(x + 3)

Factoring trinomials

x2 + bx + c  →  find two numbers that multiply to c and add to b

Factor x2 + 7x + 12

Multiply to 12, add to 7 → 3 and 4(x + 3)(x + 4)

Factor x2x − 12

Multiply to −12, add to −1 → −4 and 3(x − 4)(x + 3)

Difference of squares

a2b2 = (ab)(a + b)

x2 − 25 = x2 − 52recognize the pattern (x − 5)(x + 5)

Solving quadratic equations by factoring

Quadratic equation — usually written ax2 + bx + c = 0. When possible, factoring is the fastest method.
x2 + 7x + 12 = 0 (x + 3)(x + 4) = 0factor
Zero-product property — if ab = 0, then a = 0 or b = 0. So set each factor equal to zero.

First factor

x + 3 = 0
x = −3

Second factor

x + 4 = 0
x = −4

A quadratic can have two solutions because two different x-values may make the equation true.

Set it equal to zero first

x2 + 2x = 15not equal to zero yet x2 + 2x − 15 = 0subtract 15 (x + 5)(x − 3) = 0factor x = −5  or  x = 3
⚠ Watch out

The zero-product property only applies when the product equals zero. Factoring x2 + 2x = 15 into x(x + 2) = 15 tells you nothing.

The quadratic formula

Not every quadratic factors easily. The formula works for any ax2 + bx + c = 0.

x = b ± b2 − 4ac2aa, b, c  the coefficients, with the equation set equal to zero±  means two solutions: one with +, one with −
x2 + 2x − 1 = 0a = 1, b = 2, c = −1 x = −2 ± 22 − 4(1)(−1)2(1)substitute x = −2 ± 824 + 4 = 8 under the root x = −2 ± 2228 = 22 x = −1 ± 2divide every term by 2

With +

x = −1 + 2

With −

x = −1 − 2

Factoring or the formula?

Factors quickly → factor

x2 − 9x + 20 = 0 becomes (x − 4)(x − 5) = 0, so x = 4 or 5. No reason to use the formula.

Doesn’t factor easily → formula

The formula always works. The TSI may test whether you recognize which method is efficient, not just whether you can do the calculation.

Evaluating quadratic functions

For f(x) = ax2 + bx + c, substitute the given value for x and follow the order of operations.

f(x) = 2x2 − 3x + 4, find f(3)

f(3) = 2(3)2 − 3(3) + 4substitute= 2(9) − 9 + 4exponent first= 13

f(x) = x2 + 2x, find f(−3)

f(−3) = (−3)2 + 2(−3)parentheses around the negative= 9 − 6= 3

⚠ Watch out

When substituting a negative number, put it in parentheses. (−3)2 = 9, but −32 = −9.

Recognizing a quadratic relationship

A quadratic function doesn’t have a constant rate of change like a linear one. Its graph is a parabola — U-shaped. A positive x2 coefficient opens upward; a negative one opens downward.

You don’t need to treat every quadratic graph as its own topic, but knowing the basic shape helps with questions that compare types of functions.

y = x²

TSI strategy: factor before reaching for the formula

Write the equation as ax2 + bx + c = 0, then look for an easy factorization.

Ask

Can I find two numbers that multiply to c and add to b? If yes, factor. If not, the formula always works.

⚠ Watch out

Quadratic equations often have two solutions. Don’t stop after finding one.

🔑 Key tip

Getting the equation equal to zero is usually the key first step. Once you have ax2 + bx + c = 0, you can factor or use the formula.

And when factoring gives (xr)(xs) = 0, set each factor equal to zero. That’s how you find all the solutions.

Quadratics and Polynomials Review Quiz